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.25x^2+2.5x-2.25=0
a = .25; b = 2.5; c = -2.25;
Δ = b2-4ac
Δ = 2.52-4·.25·(-2.25)
Δ = 8.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{8.5}}{2*.25}=\frac{-2.5-\sqrt{8.5}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{8.5}}{2*.25}=\frac{-2.5+\sqrt{8.5}}{0.5} $
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